4.9x^2+9.42x-35=0

Solution for 4.9x^2+9.42x-35=0 equation:

4.9x^2+9.42x-35=0

a = 4.9; b = 9.42; c = -35;
Δ = b2-4ac
Δ = 9.422-4·4.9·(-35)
Δ = 774.7364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.42)-\sqrt{774.7364}}{2*4.9}=\frac{-9.42-\sqrt{774.7364}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.42)+\sqrt{774.7364}}{2*4.9}=\frac{-9.42+\sqrt{774.7364}}{9.8}
$